What are the solutions to the equation 0=3x^2-10x+4 ?

The solutions to the equation 0=3x^2-10x+4 are x=(5+sqrt(13))/3 ,x=(5-sqrt(13))/3

Find the zeros of 0=3x^2-10x+4

The zeros of 0=3x^2-10x+4 are x=(5+sqrt(13))/3 ,x=(5-sqrt(13))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = 3 x^{2} - 10 x + 4

x = \frac{5 + 13}{3}, x = \frac{5 - 13}{3}

Decimal Notation

x = 2.86851 \dots, x = 0.46481 \dots

Solution steps

0 = 3 x^{2} - 10 x + 4

Switch sides

3 x^{2} - 10 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

(- 10)^{2} - 4 \cdot 3 \cdot 4 = 213

x_{1, 2} = \frac{- ( - 10 ) \pm 2 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 13}{2 \cdot 3}, x_{2} = \frac{- ( - 10 ) - 2 13}{2 \cdot 3}

x = \frac{- ( - 10 ) + 2 13}{2 \cdot 3} : \frac{5 + 13}{3}

x = \frac{- ( - 10 ) - 2 13}{2 \cdot 3} : \frac{5 - 13}{3}

The solutions to the quadratic equation are:

x = \frac{5 + 13}{3}, x = \frac{5 - 13}{3}

3 x^{2} - 36 = 3 x

x, (x + 2)^{2} + (y + 1)^{2} = 0

(z - 4)^{2} = (3 - z) (1 + 2 z)

y^{2} + 4 = 6 y - 4

m^{2} = - 2

What are the solutions to the equation 0=3x^2-10x+4 ?
The solutions to the equation 0=3x^2-10x+4 are x=(5+sqrt(13))/3 ,x=(5-sqrt(13))/3
Find the zeros of 0=3x^2-10x+4
The zeros of 0=3x^2-10x+4 are x=(5+sqrt(13))/3 ,x=(5-sqrt(13))/3