What are the solutions to the equation -4b^2-3b+14=4 ?

The solutions to the equation -4b^2-3b+14=4 are b=-2,b= 5/4

Find the zeros of -4b^2-3b+14=4

The zeros of -4b^2-3b+14=4 are b=-2,b= 5/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 b^{2} - 3 b + 14 = 4

b = - 2, b = \frac{5}{4}

Decimal Notation

b = - 2, b = 1.25

Solution steps

- 4 b^{2} - 3 b + 14 = 4

Move

4

to the left side

- 4 b^{2} - 3 b + 10 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 4 ) \cdot 10}{2 ( - 4 )}

(- 3)^{2} - 4 (- 4) \cdot 10 = 13

b_{1, 2} = \frac{- ( - 3 ) \pm 13}{2 ( - 4 )}

Separate the solutions

b_{1} = \frac{- ( - 3 ) + 13}{2 ( - 4 )}, b_{2} = \frac{- ( - 3 ) - 13}{2 ( - 4 )}

b = \frac{- ( - 3 ) + 13}{2 ( - 4 )} : - 2

b = \frac{- ( - 3 ) - 13}{2 ( - 4 )} : \frac{5}{4}

The solutions to the quadratic equation are:

b = - 2, b = \frac{5}{4}

x^{2} - 2.4 x = 2.2

t^{2} - 6 = 0

3 x^{2} - 21 x + 18 = 0

z^{2} - 32 = 0

x^{2} - 15 x - 54 = 0

What are the solutions to the equation -4b^2-3b+14=4 ?
The solutions to the equation -4b^2-3b+14=4 are b=-2,b= 5/4
Find the zeros of -4b^2-3b+14=4
The zeros of -4b^2-3b+14=4 are b=-2,b= 5/4