What are the solutions to the equation -5x^2-25=0 ?

The solutions to the equation -5x^2-25=0 are x=sqrt(5)i,x=-sqrt(5)i

Find the zeros of -5x^2-25=0

The zeros of -5x^2-25=0 are x=sqrt(5)i,x=-sqrt(5)i

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- 5 x^{2} - 25 = 0

x = 5 i, x = - 5 i

Solution steps

- 5 x^{2} - 25 = 0

Move

25

to the right side

- 5 x^{2} = 25

Divide both sides by

- 5

x^{2} = - 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 5, x = - - 5

- 5 = 5 i

- - 5 = - 5 i

x = 5 i, x = - 5 i

2 x^{2} - 4 x + 1 = 2 x - 3 - x^{2}

9 = - a^{2} + 10 a

x^{2} - 4 a^{2} - b^{2} = 4 ab

m x^{2} - 2 (m + 1) x + 2 m = 0

(2 x + 5)^{2} = 16

What are the solutions to the equation -5x^2-25=0 ?
The solutions to the equation -5x^2-25=0 are x=sqrt(5)i,x=-sqrt(5)i
Find the zeros of -5x^2-25=0
The zeros of -5x^2-25=0 are x=sqrt(5)i,x=-sqrt(5)i