What are the solutions to the equation -3(x+5)^2-4=77 ?

The solutions to the equation -3(x+5)^2-4=77 are x=3sqrt(3)i-5,x=-3sqrt(3)i-5

Find the zeros of -3(x+5)^2-4=77

The zeros of -3(x+5)^2-4=77 are x=3sqrt(3)i-5,x=-3sqrt(3)i-5

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- 3 (x + 5)^{2} - 4 = 77

x = 33 i - 5, x = - 33 i - 5

Solution steps

- 3 (x + 5)^{2} - 4 = 77

Move

4

to the right side

- 3 (x + 5)^{2} = 81

Divide both sides by

- 3

(x + 5)^{2} = - 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = - 27 : x = 33 i - 5

Solve

x + 5 = - - 27 : x = - 33 i - 5

The solutions to the quadratic equation are:

x = 33 i - 5, x = - 33 i - 5

x^{2} - 99 = 0

y = \frac{1}{12} (y - 5)^{2} + 4

2 (x - 1)^{2} - 1 = 49

4 (s^{2} + 7) - 9 = 39

2 x^{2} - 8 + 6 = 0

What are the solutions to the equation -3(x+5)^2-4=77 ?
The solutions to the equation -3(x+5)^2-4=77 are x=3sqrt(3)i-5,x=-3sqrt(3)i-5
Find the zeros of -3(x+5)^2-4=77
The zeros of -3(x+5)^2-4=77 are x=3sqrt(3)i-5,x=-3sqrt(3)i-5