What are the solutions to the equation b^2-24=-5b ?

The solutions to the equation b^2-24=-5b are b=3,b=-8

Find the zeros of b^2-24=-5b

The zeros of b^2-24=-5b are b=3,b=-8

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b^{2} - 24 = - 5 b

b = 3, b = - 8

Solution steps

b^{2} - 24 = - 5 b

Move

5 b

to the left side

b^{2} - 24 + 5 b = 0

Write in the standard form

a x^{2} + b x + c = 0

b^{2} + 5 b - 24 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 24) = 11

b_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- 5 + 11}{2 \cdot 1}, b_{2} = \frac{- 5 - 11}{2 \cdot 1}

b = \frac{- 5 + 11}{2 \cdot 1} : 3

b = \frac{- 5 - 11}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

b = 3, b = - 8

9 x^{2} - 7 x - 2 = 0

6 x^{2} + 22 x + 12 = 0

3 z^{2} - 30 = 0

x^{2} + 11 = 3

x^{2} = \frac{16}{25}

What are the solutions to the equation b^2-24=-5b ?
The solutions to the equation b^2-24=-5b are b=3,b=-8
Find the zeros of b^2-24=-5b
The zeros of b^2-24=-5b are b=3,b=-8