What are the solutions to the equation -x^2+78x+460=1581 ?

The solutions to the equation -x^2+78x+460=1581 are x=19,x=59

Find the zeros of -x^2+78x+460=1581

The zeros of -x^2+78x+460=1581 are x=19,x=59

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- x^{2} + 78 x + 460 = 1581

x = 19, x = 59

Solution steps

- x^{2} + 78 x + 460 = 1581

Move

1581

to the left side

- x^{2} + 78 x - 1121 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 78 \pm 7 8 ^{2} - 4 ( - 1 ) ( - 1121 )}{2 ( - 1 )}

7 8^{2} - 4 (- 1) (- 1121) = 40

x_{1, 2} = \frac{- 78 \pm 40}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 78 + 40}{2 ( - 1 )}, x_{2} = \frac{- 78 - 40}{2 ( - 1 )}

x = \frac{- 78 + 40}{2 ( - 1 )} : 19

x = \frac{- 78 - 40}{2 ( - 1 )} : 59

The solutions to the quadratic equation are:

x = 19, x = 59

5 + 5 x^{2} - 2 x = 3 x^{2} - 4

3 x^{2} - 4 x - 11 = 0

(3 x - 4)^{2} = 9

(3 x - 4)^{2} = 0

0.1 x^{2} + 36 x + 480 = 50 x

What are the solutions to the equation -x^2+78x+460=1581 ?
The solutions to the equation -x^2+78x+460=1581 are x=19,x=59
Find the zeros of -x^2+78x+460=1581
The zeros of -x^2+78x+460=1581 are x=19,x=59