What are the solutions to the equation x^2+3x=36 ?

The solutions to the equation x^2+3x=36 are x=(-3+3sqrt(17))/2 ,x=(-3-3sqrt(17))/2

Find the zeros of x^2+3x=36

The zeros of x^2+3x=36 are x=(-3+3sqrt(17))/2 ,x=(-3-3sqrt(17))/2

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x^{2} + 3 x = 36

x = \frac{- 3 + 3 17}{2}, x = \frac{- 3 - 3 17}{2}

Decimal Notation

x = 4.68465 \dots, x = - 7.68465 \dots

Solution steps

x^{2} + 3 x = 36

Move

36

to the left side

x^{2} + 3 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 36) = 317

x_{1, 2} = \frac{- 3 \pm 3 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 3 17}{2 \cdot 1}, x_{2} = \frac{- 3 - 3 17}{2 \cdot 1}

x = \frac{- 3 + 3 17}{2 \cdot 1} : \frac{- 3 + 3 17}{2}

x = \frac{- 3 - 3 17}{2 \cdot 1} : \frac{- 3 - 3 17}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 3 17}{2}, x = \frac{- 3 - 3 17}{2}

x^{2} + 3 x = 12

x^{2} + 3 x = - 3

5 x^{2} + 7 x = - 1

4 m^{2} - 14 m + 10 = 0

5^{2} + 1 5^{2} = x^{2}

What are the solutions to the equation x^2+3x=36 ?
The solutions to the equation x^2+3x=36 are x=(-3+3sqrt(17))/2 ,x=(-3-3sqrt(17))/2
Find the zeros of x^2+3x=36
The zeros of x^2+3x=36 are x=(-3+3sqrt(17))/2 ,x=(-3-3sqrt(17))/2