What is (2^{-2}m^{-3})/(n^0) ?

The solution to (2^{-2}m^{-3})/(n^0) is 1/(4m^3)

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simplify (2^{-2}m^{-3})/(n^0)

simplify

\frac{2 ^{- 2} m ^{- 3}}{n ^{0}}

\frac{1}{4 m ^{3}}

Solution steps

\frac{2 ^{- 2} m ^{- 3}}{n ^{0}}

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

n^{0} = 1

= \frac{2 ^{- 2} m ^{- 3}}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 2^{- 2} m^{- 3}

Simplify

2^{- 2} m^{- 3} : \frac{1}{4 m ^{3}}

= \frac{1}{4 m ^{3}}

(2 x^{3} y^{- \frac{1}{4}})^{2} (8 y^{- \frac{3}{2}})^{- \frac{1}{3}}

10 v - 80 \geq 5 (4 - 2 v)

\frac{b ^{7}}{b ^{6}}

∣ x - 3 ∣ < 3 x - 4

n^{2} + 4 n + 4