What are the solutions to the equation 25x^2+40x+16=28 ?

The solutions to the equation 25x^2+40x+16=28 are x=(2(sqrt(7)-2))/5 ,x=-(2(2+sqrt(7)))/5

Find the zeros of 25x^2+40x+16=28

The zeros of 25x^2+40x+16=28 are x=(2(sqrt(7)-2))/5 ,x=-(2(2+sqrt(7)))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25 x^{2} + 40 x + 16 = 28

x = \frac{2 ( 7 - 2 )}{5}, x = - \frac{2 ( 2 + 7 )}{5}

Decimal Notation

x = 0.25830 \dots, x = - 1.85830 \dots

Solution steps

25 x^{2} + 40 x + 16 = 28

Move

28

to the left side

25 x^{2} + 40 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 25 ( - 12 )}{2 \cdot 25}

4 0^{2} - 4 \cdot 25 (- 12) = 207

x_{1, 2} = \frac{- 40 \pm 20 7}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- 40 + 20 7}{2 \cdot 25}, x_{2} = \frac{- 40 - 20 7}{2 \cdot 25}

x = \frac{- 40 + 20 7}{2 \cdot 25} : \frac{2 ( 7 - 2 )}{5}

x = \frac{- 40 - 20 7}{2 \cdot 25} : - \frac{2 ( 2 + 7 )}{5}

The solutions to the quadratic equation are:

x = \frac{2 ( 7 - 2 )}{5}, x = - \frac{2 ( 2 + 7 )}{5}

6 v^{2} + 30 v = 0

x^{2} - 6 - 27 = 0

4 x^{2} + 3 x + 4 = 0

14 x^{2} + 7 x = 4 x^{2} - 1

x^{2} - \frac{1}{5} x - \frac{11}{5} = 0

What are the solutions to the equation 25x^2+40x+16=28 ?
The solutions to the equation 25x^2+40x+16=28 are x=(2(sqrt(7)-2))/5 ,x=-(2(2+sqrt(7)))/5
Find the zeros of 25x^2+40x+16=28
The zeros of 25x^2+40x+16=28 are x=(2(sqrt(7)-2))/5 ,x=-(2(2+sqrt(7)))/5