What are the solutions to the equation (1-3)x^2-(3+1)x-2=0 ?

The solutions to the equation (1-3)x^2-(3+1)x-2=0 are x=-1

Find the zeros of (1-3)x^2-(3+1)x-2=0

The zeros of (1-3)x^2-(3+1)x-2=0 are x=-1

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(1 - 3) x^{2} - (3 + 1) x - 2 = 0

x = - 1

Solution steps

(1 - 3) x^{2} - (3 + 1) x - 2 = 0

Expand

(1 - 3) x^{2} - (3 + 1) x - 2 : - 2 x^{2} - 4 x - 2

- 2 x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) ( - 2 )}{2 ( - 2 )}

(- 4)^{2} - 4 (- 2) (- 2) = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 ( - 2 )}

x = \frac{- ( - 4 )}{2 ( - 2 )}

\frac{- ( - 4 )}{2 ( - 2 )} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

3 x^{2} + 12 = 3

5 x^{2} - x - 108 = 0

(x + 2) 2 - x^{2} = 60

4 x^{2} - \frac{5}{2} x - 3 = 0

x^{2} - 14 x + 30 = 0

What are the solutions to the equation (1-3)x^2-(3+1)x-2=0 ?
The solutions to the equation (1-3)x^2-(3+1)x-2=0 are x=-1
Find the zeros of (1-3)x^2-(3+1)x-2=0
The zeros of (1-3)x^2-(3+1)x-2=0 are x=-1