What are the solutions to the equation 10x^2+8x-9=0 ?

The solutions to the equation 10x^2+8x-9=0 are x=(-4+sqrt(106))/(10),x=-(4+sqrt(106))/(10)

Find the zeros of 10x^2+8x-9=0

The zeros of 10x^2+8x-9=0 are x=(-4+sqrt(106))/(10),x=-(4+sqrt(106))/(10)

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10 x^{2} + 8 x - 9 = 0

x = \frac{- 4 + 106}{10}, x = - \frac{4 + 106}{10}

Decimal Notation

x = 0.62956 \dots, x = - 1.42956 \dots

Solution steps

10 x^{2} + 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 10 ( - 9 )}{2 \cdot 10}

8^{2} - 4 \cdot 10 (- 9) = 2106

x_{1, 2} = \frac{- 8 \pm 2 106}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 8 + 2 106}{2 \cdot 10}, x_{2} = \frac{- 8 - 2 106}{2 \cdot 10}

x = \frac{- 8 + 2 106}{2 \cdot 10} : \frac{- 4 + 106}{10}

x = \frac{- 8 - 2 106}{2 \cdot 10} : - \frac{4 + 106}{10}

The solutions to the quadratic equation are:

x = \frac{- 4 + 106}{10}, x = - \frac{4 + 106}{10}

x, 2 x^{2} - 3 y^{2} - 20 x - 18 y + 23 = 0

- 2 x^{2} = - 242

- 3 x^{2} + 12 x + 36 = 0

p^{2} - 16 = 0

x, x^{2} + 25 = 0

What are the solutions to the equation 10x^2+8x-9=0 ?
The solutions to the equation 10x^2+8x-9=0 are x=(-4+sqrt(106))/(10),x=-(4+sqrt(106))/(10)
Find the zeros of 10x^2+8x-9=0
The zeros of 10x^2+8x-9=0 are x=(-4+sqrt(106))/(10),x=-(4+sqrt(106))/(10)