What are the solutions to the equation 3x^2+5=5x^2-8 ?

The solutions to the equation 3x^2+5=5x^2-8 are x=sqrt(13/2),x=-sqrt(13/2)

Find the zeros of 3x^2+5=5x^2-8

The zeros of 3x^2+5=5x^2-8 are x=sqrt(13/2),x=-sqrt(13/2)

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3 x^{2} + 5 = 5 x^{2} - 8

x = \frac{13}{2}, x = - \frac{13}{2}

Decimal Notation

x = 2.54950 \dots, x = - 2.54950 \dots

Solution steps

3 x^{2} + 5 = 5 x^{2} - 8

Move

5

to the right side

3 x^{2} = 5 x^{2} - 13

Move

5 x^{2}

to the left side

- 2 x^{2} = - 13

Divide both sides by

- 2

x^{2} = \frac{13}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{13}{2}, x = - \frac{13}{2}

220 + 11 x - 11 x^{2} = 11 x^{2} - 55 x

8 x^{2} + 4 x + 2 = 0

0 = 12 x^{2} - 24 x + 9

x^{2} + 7 x - 14 = 0

2 x^{2} - 7 x + 2

What are the solutions to the equation 3x^2+5=5x^2-8 ?
The solutions to the equation 3x^2+5=5x^2-8 are x=sqrt(13/2),x=-sqrt(13/2)
Find the zeros of 3x^2+5=5x^2-8
The zeros of 3x^2+5=5x^2-8 are x=sqrt(13/2),x=-sqrt(13/2)