What are the solutions to the equation 3(-6+x)^2+2(-6)=0 ?

The solutions to the equation 3(-6+x)^2+2(-6)=0 are x=8,x=4

Find the zeros of 3(-6+x)^2+2(-6)=0

The zeros of 3(-6+x)^2+2(-6)=0 are x=8,x=4

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3 (- 6 + x)^{2} + 2 (- 6) = 0

x = 8, x = 4

Solution steps

3 (- 6 + x)^{2} + 2 (- 6) = 0

Move

2 (- 6)

to the right side

3 (- 6 + x)^{2} = 12

Divide both sides by

3

(- 6 + x)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

- 6 + x = 4 : x = 8

Solve

- 6 + x = - 4 : x = 4

The solutions to the quadratic equation are:

x = 8, x = 4

x, x^{2} + 2 x - 1 = 0

\frac{5}{2} x^{2} - \frac{35}{6} x + \frac{5}{3} = 0

x, y^{2} + x y - x^{2} = 5

3 x^{2} - 3 x - 1 = x^{2} + 2

9 x^{2} - 28 x + 20 = 0

What are the solutions to the equation 3(-6+x)^2+2(-6)=0 ?
The solutions to the equation 3(-6+x)^2+2(-6)=0 are x=8,x=4
Find the zeros of 3(-6+x)^2+2(-6)=0
The zeros of 3(-6+x)^2+2(-6)=0 are x=8,x=4