What are the solutions to the equation x^2-8x=-4 ?

The solutions to the equation x^2-8x=-4 are x=2(2+sqrt(3)),x=2(2-sqrt(3))

Find the zeros of x^2-8x=-4

The zeros of x^2-8x=-4 are x=2(2+sqrt(3)),x=2(2-sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 8 x = - 4

x = 2 (2 + 3), x = 2 (2 - 3)

Decimal Notation

x = 7.46410 \dots, x = 0.53589 \dots

Solution steps

x^{2} - 8 x = - 4

Move

4

to the left side

x^{2} - 8 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 4 = 43

x_{1, 2} = \frac{- ( - 8 ) \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 3}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 4 3}{2 \cdot 1}

x = \frac{- ( - 8 ) + 4 3}{2 \cdot 1} : 2 (2 + 3)

x = \frac{- ( - 8 ) - 4 3}{2 \cdot 1} : 2 (2 - 3)

The solutions to the quadratic equation are:

x = 2 (2 + 3), x = 2 (2 - 3)

x^{2} = 5 x - 9

x, x^{2} + y^{3} - 9 = 0

x, 3 x^{2} - 8 x y - 12 y^{2} - 30 x - 64 y = 0

5 x^{2} + 0 x - 13 = 0

8 z^{2} - 200 = 0

What are the solutions to the equation x^2-8x=-4 ?
The solutions to the equation x^2-8x=-4 are x=2(2+sqrt(3)),x=2(2-sqrt(3))
Find the zeros of x^2-8x=-4
The zeros of x^2-8x=-4 are x=2(2+sqrt(3)),x=2(2-sqrt(3))