What are the solutions to the equation 0=-4.9t^2+900t ?

The solutions to the equation 0=-4.9t^2+900t are t=0,t= 9000/49

Find the zeros of 0=-4.9t^2+900t

The zeros of 0=-4.9t^2+900t are t=0,t= 9000/49

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0 = - 4.9 t^{2} + 900 t

t = 0, t = \frac{9000}{49}

Decimal Notation

t = 0, t = 183.67346 \dots

Solution steps

0 = - 4.9 t^{2} + 900 t

Multiply both sides by

10

0 = - 49 t^{2} + 9000 t

Switch sides

- 49 t^{2} + 9000 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 9000 \pm 900 0 ^{2} - 4 ( - 49 ) \cdot 0}{2 ( - 49 )}

900 0^{2} - 4 (- 49) \cdot 0 = 9000

t_{1, 2} = \frac{- 9000 \pm 9000}{2 ( - 49 )}

Separate the solutions

t_{1} = \frac{- 9000 + 9000}{2 ( - 49 )}, t_{2} = \frac{- 9000 - 9000}{2 ( - 49 )}

t = \frac{- 9000 + 9000}{2 ( - 49 )} : 0

t = \frac{- 9000 - 9000}{2 ( - 49 )} : \frac{9000}{49}

The solutions to the quadratic equation are:

t = 0, t = \frac{9000}{49}

x, k x^{2} - 4 x + \frac{1}{2} = 0

(2 x + 6) (2 x - 6) = (2 x + 9) (3 x - 4)

- 3 (x - 8) (5 x - 1) = 0

3 X^{2} - 75 = 0

x, x^{2} - k x + 2 = 0

What are the solutions to the equation 0=-4.9t^2+900t ?
The solutions to the equation 0=-4.9t^2+900t are t=0,t= 9000/49
Find the zeros of 0=-4.9t^2+900t
The zeros of 0=-4.9t^2+900t are t=0,t= 9000/49