What are the solutions to the equation 12x^2-24x-40=0 ?

The solutions to the equation 12x^2-24x-40=0 are x=(3+sqrt(39))/3 ,x=(3-sqrt(39))/3

Find the zeros of 12x^2-24x-40=0

The zeros of 12x^2-24x-40=0 are x=(3+sqrt(39))/3 ,x=(3-sqrt(39))/3

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12 x^{2} - 24 x - 40 = 0

x = \frac{3 + 39}{3}, x = \frac{3 - 39}{3}

Decimal Notation

x = 3.08166 \dots, x = - 1.08166 \dots

Solution steps

12 x^{2} - 24 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 12 ( - 40 )}{2 \cdot 12}

(- 24)^{2} - 4 \cdot 12 (- 40) = 839

x_{1, 2} = \frac{- ( - 24 ) \pm 8 39}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 8 39}{2 \cdot 12}, x_{2} = \frac{- ( - 24 ) - 8 39}{2 \cdot 12}

x = \frac{- ( - 24 ) + 8 39}{2 \cdot 12} : \frac{3 + 39}{3}

x = \frac{- ( - 24 ) - 8 39}{2 \cdot 12} : \frac{3 - 39}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 39}{3}, x = \frac{3 - 39}{3}

25 - x^{2} = 9

x^{2} - 25

1.371 6^{2} = x^{2} + (\frac{1.3716}{2})^{2}

7 x^{2} - 5 = 23

lo g_{10} (5) (3 x^{2} - 3) - lo g_{10} (5) (x + 5) = 1

What are the solutions to the equation 12x^2-24x-40=0 ?
The solutions to the equation 12x^2-24x-40=0 are x=(3+sqrt(39))/3 ,x=(3-sqrt(39))/3
Find the zeros of 12x^2-24x-40=0
The zeros of 12x^2-24x-40=0 are x=(3+sqrt(39))/3 ,x=(3-sqrt(39))/3