What are the solutions to the equation 8x^2-16x+1=0 ?

The solutions to the equation 8x^2-16x+1=0 are x=(4+sqrt(14))/4 ,x=(4-sqrt(14))/4

Find the zeros of 8x^2-16x+1=0

The zeros of 8x^2-16x+1=0 are x=(4+sqrt(14))/4 ,x=(4-sqrt(14))/4

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8 x^{2} - 16 x + 1 = 0

x = \frac{4 + 14}{4}, x = \frac{4 - 14}{4}

Decimal Notation

x = 1.93541 \dots, x = 0.06458 \dots

Solution steps

8 x^{2} - 16 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 8 \cdot 1}{2 \cdot 8}

(- 16)^{2} - 4 \cdot 8 \cdot 1 = 414

x_{1, 2} = \frac{- ( - 16 ) \pm 4 14}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 14}{2 \cdot 8}, x_{2} = \frac{- ( - 16 ) - 4 14}{2 \cdot 8}

x = \frac{- ( - 16 ) + 4 14}{2 \cdot 8} : \frac{4 + 14}{4}

x = \frac{- ( - 16 ) - 4 14}{2 \cdot 8} : \frac{4 - 14}{4}

The solutions to the quadratic equation are:

x = \frac{4 + 14}{4}, x = \frac{4 - 14}{4}

x^{2} = \frac{25}{49}

5 x^{2} - 30 x - 7 = - 7

x^{2} + 2 = 83

x^{2} + 2 = 18

(3 x - 4)^{2} - 6 = (2 x - 5)^{2}

What are the solutions to the equation 8x^2-16x+1=0 ?
The solutions to the equation 8x^2-16x+1=0 are x=(4+sqrt(14))/4 ,x=(4-sqrt(14))/4
Find the zeros of 8x^2-16x+1=0
The zeros of 8x^2-16x+1=0 are x=(4+sqrt(14))/4 ,x=(4-sqrt(14))/4