What are the solutions to the equation 4x^2-9x-90=0 ?

The solutions to the equation 4x^2-9x-90=0 are x=6,x=-15/4

Find the zeros of 4x^2-9x-90=0

The zeros of 4x^2-9x-90=0 are x=6,x=-15/4

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4 x^{2} - 9 x - 90 = 0

x = 6, x = - \frac{15}{4}

Decimal Notation

x = 6, x = - 3.75

Solution steps

4 x^{2} - 9 x - 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 ( - 90 )}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 (- 90) = 39

x_{1, 2} = \frac{- ( - 9 ) \pm 39}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 39}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 39}{2 \cdot 4}

x = \frac{- ( - 9 ) + 39}{2 \cdot 4} : 6

x = \frac{- ( - 9 ) - 39}{2 \cdot 4} : - \frac{15}{4}

The solutions to the quadratic equation are:

x = 6, x = - \frac{15}{4}

- 0.1 x^{2} + 80 = 0.3 x^{2} + x + 30

8 x^{2} + 16 x = 42

x, x^{2} = 2 y^{2} lo g_{10} (y)

5 x^{2} - 20 x + 10 = 0

5 x^{2} - 6 x - 14 = - 6

What are the solutions to the equation 4x^2-9x-90=0 ?
The solutions to the equation 4x^2-9x-90=0 are x=6,x=-15/4
Find the zeros of 4x^2-9x-90=0
The zeros of 4x^2-9x-90=0 are x=6,x=-15/4