What are the solutions to the equation 2x^2-6x+9/2 =0 ?

The solutions to the equation 2x^2-6x+9/2 =0 are x= 3/2

Find the zeros of 2x^2-6x+9/2 =0

The zeros of 2x^2-6x+9/2 =0 are x= 3/2

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2 x^{2} - 6 x + \frac{9}{2} = 0

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

2 x^{2} - 6 x + \frac{9}{2} = 0

Multiply both sides by

2

4 x^{2} - 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

x = \frac{3}{2}

The solution to the quadratic equation is:

x = \frac{3}{2}

(3 x - 1)^{2} = x^{2} + 21

x^{2} = - x^{2} + 2 x + 4

x^{2} - 40 x + 256 = 0

k^{2} - 6 k + 1 = 0

x, x^{2} - 3 x + 4 = 0

What are the solutions to the equation 2x^2-6x+9/2 =0 ?
The solutions to the equation 2x^2-6x+9/2 =0 are x= 3/2
Find the zeros of 2x^2-6x+9/2 =0
The zeros of 2x^2-6x+9/2 =0 are x= 3/2