What are the solutions to the equation x^2-4x+3.5=0 ?

The solutions to the equation x^2-4x+3.5=0 are x=(4+sqrt(2))/2 ,x=(4-sqrt(2))/2

Find the zeros of x^2-4x+3.5=0

The zeros of x^2-4x+3.5=0 are x=(4+sqrt(2))/2 ,x=(4-sqrt(2))/2

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x^{2} - 4 x + 3.5 = 0

x = \frac{4 + 2}{2}, x = \frac{4 - 2}{2}

Decimal Notation

x = 2.70710 \dots, x = 1.29289 \dots

Solution steps

x^{2} - 4 x + 3.5 = 0

Multiply both sides by

10

10 x^{2} - 40 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 10 \cdot 35}{2 \cdot 10}

(- 40)^{2} - 4 \cdot 10 \cdot 35 = 102

x_{1, 2} = \frac{- ( - 40 ) \pm 10 2}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 10 2}{2 \cdot 10}, x_{2} = \frac{- ( - 40 ) - 10 2}{2 \cdot 10}

x = \frac{- ( - 40 ) + 10 2}{2 \cdot 10} : \frac{4 + 2}{2}

x = \frac{- ( - 40 ) - 10 2}{2 \cdot 10} : \frac{4 - 2}{2}

The solutions to the quadratic equation are:

x = \frac{4 + 2}{2}, x = \frac{4 - 2}{2}

x^{2} + 5 = 7

8 x^{2} + 10 x + 5 = 0

x^{2} + 2 = x

\frac{1}{4} x^{2} - 12 = - 3

x^{2} + 12 x + 36 = 49

What are the solutions to the equation x^2-4x+3.5=0 ?
The solutions to the equation x^2-4x+3.5=0 are x=(4+sqrt(2))/2 ,x=(4-sqrt(2))/2
Find the zeros of x^2-4x+3.5=0
The zeros of x^2-4x+3.5=0 are x=(4+sqrt(2))/2 ,x=(4-sqrt(2))/2