What are the solutions to the equation x(2x-7)=-6 ?

The solutions to the equation x(2x-7)=-6 are x=2,x= 3/2

Find the zeros of x(2x-7)=-6

The zeros of x(2x-7)=-6 are x=2,x= 3/2

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x (2 x - 7) = - 6

x = 2, x = \frac{3}{2}

Decimal Notation

x = 2, x = 1.5

Solution steps

x (2 x - 7) = - 6

Expand

x (2 x - 7) : 2 x^{2} - 7 x

2 x^{2} - 7 x = - 6

Move

6

to the left side

2 x^{2} - 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 \cdot 6 = 1

x_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 2}

x = \frac{- ( - 7 ) + 1}{2 \cdot 2} : 2

x = \frac{- ( - 7 ) - 1}{2 \cdot 2} : \frac{3}{2}

The solutions to the quadratic equation are:

x = 2, x = \frac{3}{2}

x, x^{2} + y^{2} = 2 x y + 3

n^{2} + 4 n - 32 = 0

- 2 x^{2} + 5 x + 3

5.400447427 x^{2} + 8.145 x - 41.59 = 0

6 x^{2} = - 11 x + 10

What are the solutions to the equation x(2x-7)=-6 ?
The solutions to the equation x(2x-7)=-6 are x=2,x= 3/2
Find the zeros of x(2x-7)=-6
The zeros of x(2x-7)=-6 are x=2,x= 3/2