What are the solutions to the equation 9x^2+6x+10=0 ?

The solutions to the equation 9x^2+6x+10=0 are x=-1/3+i,x=-1/3-i

Find the zeros of 9x^2+6x+10=0

The zeros of 9x^2+6x+10=0 are x=-1/3+i,x=-1/3-i

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9 x^{2} + 6 x + 10 = 0

x = - \frac{1}{3} + i, x = - \frac{1}{3} - i

Solution steps

9 x^{2} + 6 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 10}{2 \cdot 9}

Simplify

6^{2} - 4 \cdot 9 \cdot 10 : 18 i

x_{1, 2} = \frac{- 6 \pm 18 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 6 + 18 i}{2 \cdot 9}, x_{2} = \frac{- 6 - 18 i}{2 \cdot 9}

x = \frac{- 6 + 18 i}{2 \cdot 9} : - \frac{1}{3} + i

x = \frac{- 6 - 18 i}{2 \cdot 9} : - \frac{1}{3} - i

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i, x = - \frac{1}{3} - i

v^{2} - 3 v - 4 = 0

x^{2} - 198 = 0

v^{2} = 24.01

50 = 2.332 x^{2} + 15.335 x + 85.665

\frac{x ^{2}}{5} = 45

What are the solutions to the equation 9x^2+6x+10=0 ?
The solutions to the equation 9x^2+6x+10=0 are x=-1/3+i,x=-1/3-i
Find the zeros of 9x^2+6x+10=0
The zeros of 9x^2+6x+10=0 are x=-1/3+i,x=-1/3-i