What are the solutions to the equation 4q^2+8q+10=0 ?

The solutions to the equation 4q^2+8q+10=0 are q=-1+isqrt(3/2),q=-1-isqrt(3/2)

Find the zeros of 4q^2+8q+10=0

The zeros of 4q^2+8q+10=0 are q=-1+isqrt(3/2),q=-1-isqrt(3/2)

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4 q^{2} + 8 q + 10 = 0

q = - 1 + i \frac{3}{2}, q = - 1 - i \frac{3}{2}

Solution steps

4 q^{2} + 8 q + 10 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 10}{2 \cdot 4}

Simplify

8^{2} - 4 \cdot 4 \cdot 10 : 46 i

q_{1, 2} = \frac{- 8 \pm 4 6 i}{2 \cdot 4}

Separate the solutions

q_{1} = \frac{- 8 + 4 6 i}{2 \cdot 4}, q_{2} = \frac{- 8 - 4 6 i}{2 \cdot 4}

q = \frac{- 8 + 4 6 i}{2 \cdot 4} : - 1 + i \frac{3}{2}

q = \frac{- 8 - 4 6 i}{2 \cdot 4} : - 1 - i \frac{3}{2}

The solutions to the quadratic equation are:

q = - 1 + i \frac{3}{2}, q = - 1 - i \frac{3}{2}

200 = \frac{1}{3} \cdot x^{2} \cdot 3.142 \cdot 12

3 x^{2} + 5 x = 10

12 x^{2} - 72 x + 104 = 0

x^{2} + 4 x + 8 = 0

(5 x + 1)^{2} = 196

What are the solutions to the equation 4q^2+8q+10=0 ?
The solutions to the equation 4q^2+8q+10=0 are q=-1+isqrt(3/2),q=-1-isqrt(3/2)
Find the zeros of 4q^2+8q+10=0
The zeros of 4q^2+8q+10=0 are q=-1+isqrt(3/2),q=-1-isqrt(3/2)