What are the solutions to the equation 7x^2-2x+1=0 ?

The solutions to the equation 7x^2-2x+1=0 are x= 1/7+i(sqrt(6))/7 ,x= 1/7-i(sqrt(6))/7

Find the zeros of 7x^2-2x+1=0

The zeros of 7x^2-2x+1=0 are x= 1/7+i(sqrt(6))/7 ,x= 1/7-i(sqrt(6))/7

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7 x^{2} - 2 x + 1 = 0

x = \frac{1}{7} + i \frac{6}{7}, x = \frac{1}{7} - i \frac{6}{7}

Solution steps

7 x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 7 \cdot 1}{2 \cdot 7}

Simplify

(- 2)^{2} - 4 \cdot 7 \cdot 1 : 26 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 6 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 6 i}{2 \cdot 7}, x_{2} = \frac{- ( - 2 ) - 2 6 i}{2 \cdot 7}

x = \frac{- ( - 2 ) + 2 6 i}{2 \cdot 7} : \frac{1}{7} + i \frac{6}{7}

x = \frac{- ( - 2 ) - 2 6 i}{2 \cdot 7} : \frac{1}{7} - i \frac{6}{7}

The solutions to the quadratic equation are:

x = \frac{1}{7} + i \frac{6}{7}, x = \frac{1}{7} - i \frac{6}{7}

6 x^{2} - 6 x + 4 = 0

24 = x^{2} + 2 x

(x + 8) (x + 5) = 0

x^{2} = \frac{1}{64}

7 x^{2} = 7 x

What are the solutions to the equation 7x^2-2x+1=0 ?
The solutions to the equation 7x^2-2x+1=0 are x= 1/7+i(sqrt(6))/7 ,x= 1/7-i(sqrt(6))/7
Find the zeros of 7x^2-2x+1=0
The zeros of 7x^2-2x+1=0 are x= 1/7+i(sqrt(6))/7 ,x= 1/7-i(sqrt(6))/7