What are the solutions to the equation 0=2x^2+x-10 ?

The solutions to the equation 0=2x^2+x-10 are x=2,x=-5/2

Find the zeros of 0=2x^2+x-10

The zeros of 0=2x^2+x-10 are x=2,x=-5/2

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0 = 2 x^{2} + x - 10

x = 2, x = - \frac{5}{2}

Decimal Notation

x = 2, x = - 2.5

Solution steps

0 = 2 x^{2} + x - 10

Switch sides

2 x^{2} + x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 10) = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 \cdot 2}, x_{2} = \frac{- 1 - 9}{2 \cdot 2}

x = \frac{- 1 + 9}{2 \cdot 2} : 2

x = \frac{- 1 - 9}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{5}{2}

X (X + 3) = 5 X + 3

x, x y + x^{2} = 1607

3 y^{2} + 7 y - 7 = 0

2 x^{2} + 10 x - 15 = 0

- 2 x^{2} + 12 x - 13 = 0

What are the solutions to the equation 0=2x^2+x-10 ?
The solutions to the equation 0=2x^2+x-10 are x=2,x=-5/2
Find the zeros of 0=2x^2+x-10
The zeros of 0=2x^2+x-10 are x=2,x=-5/2