What are the solutions to the equation λ^2-9λ+18=0 ?

The solutions to the equation λ^2-9λ+18=0 are λ=6,λ=3

Find the zeros of λ^2-9λ+18=0

The zeros of λ^2-9λ+18=0 are λ=6,λ=3

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λ^{2} - 9 λ + 18 = 0

λ = 6, λ = 3

Solution steps

λ^{2} - 9 λ + 18 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 18 = 3

λ_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 1}

Separate the solutions

λ_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 1}, λ_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 1}

λ = \frac{- ( - 9 ) + 3}{2 \cdot 1} : 6

λ = \frac{- ( - 9 ) - 3}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

λ = 6, λ = 3

x^{2} = 2 4^{2} + 2 6^{2}

(D^{2} + 1) = 0

0 = 3 x^{2} - 9 x - 54

- 9 x^{2} + 18 x + 135 = 0

x^{2} + 32 x = 0

What are the solutions to the equation λ^2-9λ+18=0 ?
The solutions to the equation λ^2-9λ+18=0 are λ=6,λ=3
Find the zeros of λ^2-9λ+18=0
The zeros of λ^2-9λ+18=0 are λ=6,λ=3