What are the solutions to the equation x^2-x-49=0 ?

The solutions to the equation x^2-x-49=0 are x=(1+sqrt(197))/2 ,x=(1-sqrt(197))/2

Find the zeros of x^2-x-49=0

The zeros of x^2-x-49=0 are x=(1+sqrt(197))/2 ,x=(1-sqrt(197))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - x - 49 = 0

x = \frac{1 + 197}{2}, x = \frac{1 - 197}{2}

Decimal Notation

x = 7.51783 \dots, x = - 6.51783 \dots

Solution steps

x^{2} - x - 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 49 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 49) = 197

x_{1, 2} = \frac{- ( - 1 ) \pm 197}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 197}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 197}{2 \cdot 1}

x = \frac{- ( - 1 ) + 197}{2 \cdot 1} : \frac{1 + 197}{2}

x = \frac{- ( - 1 ) - 197}{2 \cdot 1} : \frac{1 - 197}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 197}{2}, x = \frac{1 - 197}{2}

- 2 x^{2} + 44 x - 235

p^{2} + 2 p - 3 = 0

2 x^{2} + 4 x - 32 = 0

x^{2} - 32 x + c

x, x^{2} - 8 = 0

What are the solutions to the equation x^2-x-49=0 ?
The solutions to the equation x^2-x-49=0 are x=(1+sqrt(197))/2 ,x=(1-sqrt(197))/2
Find the zeros of x^2-x-49=0
The zeros of x^2-x-49=0 are x=(1+sqrt(197))/2 ,x=(1-sqrt(197))/2