What are the solutions to the equation 4x^2-9x+20=0 ?

The solutions to the equation 4x^2-9x+20=0 are x= 9/8+i(sqrt(239))/8 ,x= 9/8-i(sqrt(239))/8

Find the zeros of 4x^2-9x+20=0

The zeros of 4x^2-9x+20=0 are x= 9/8+i(sqrt(239))/8 ,x= 9/8-i(sqrt(239))/8

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4 x^{2} - 9 x + 20 = 0

x = \frac{9}{8} + i \frac{239}{8}, x = \frac{9}{8} - i \frac{239}{8}

Solution steps

4 x^{2} - 9 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 \cdot 20}{2 \cdot 4}

Simplify

(- 9)^{2} - 4 \cdot 4 \cdot 20 : 239 i

x_{1, 2} = \frac{- ( - 9 ) \pm 239 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 239 i}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 239 i}{2 \cdot 4}

x = \frac{- ( - 9 ) + 239 i}{2 \cdot 4} : \frac{9}{8} + i \frac{239}{8}

x = \frac{- ( - 9 ) - 239 i}{2 \cdot 4} : \frac{9}{8} - i \frac{239}{8}

The solutions to the quadratic equation are:

x = \frac{9}{8} + i \frac{239}{8}, x = \frac{9}{8} - i \frac{239}{8}

12 x^{2} - x = 6

\frac{9}{169} + \frac{y ^{2}}{100} = 1

c^{2} = 5^{2} - 3^{2}

x, x^{2} - 3 = 0

3 x^{2} + 7 x - 11 = 0

What are the solutions to the equation 4x^2-9x+20=0 ?
The solutions to the equation 4x^2-9x+20=0 are x= 9/8+i(sqrt(239))/8 ,x= 9/8-i(sqrt(239))/8
Find the zeros of 4x^2-9x+20=0
The zeros of 4x^2-9x+20=0 are x= 9/8+i(sqrt(239))/8 ,x= 9/8-i(sqrt(239))/8