What are the solutions to the equation 2b^2=32 ?

The solutions to the equation 2b^2=32 are b=4,b=-4

Find the zeros of 2b^2=32

The zeros of 2b^2=32 are b=4,b=-4

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2 b^{2} = 32

b = 4, b = - 4

Solution steps

2 b^{2} = 32

Divide both sides by

2

b^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 16, b = - 16

16 = 4

- 16 = - 4

b = 4, b = - 4

3 x^{2} + 1 x = 0

x^{2} + 5 x - 6 = 0

2^{2} + b^{2} = 1 1^{2}

y, x y - 1 = x + y^{2}

(k - 2) x^{2} - 5 x + 2 k = 0.6

What are the solutions to the equation 2b^2=32 ?
The solutions to the equation 2b^2=32 are b=4,b=-4
Find the zeros of 2b^2=32
The zeros of 2b^2=32 are b=4,b=-4