What are the solutions to the equation 4x^2+64x=0 ?

The solutions to the equation 4x^2+64x=0 are x=0,x=-16

Find the zeros of 4x^2+64x=0

The zeros of 4x^2+64x=0 are x=0,x=-16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 64 x = 0

x = 0, x = - 16

Solution steps

4 x^{2} + 64 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

6 4^{2} - 4 \cdot 4 \cdot 0 = 64

x_{1, 2} = \frac{- 64 \pm 64}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 64 + 64}{2 \cdot 4}, x_{2} = \frac{- 64 - 64}{2 \cdot 4}

x = \frac{- 64 + 64}{2 \cdot 4} : 0

x = \frac{- 64 - 64}{2 \cdot 4} : - 16

The solutions to the quadratic equation are:

x = 0, x = - 16

36 s^{2} - 12 s + 1 = 0

4 = - 16 t^{2} + 32 t + 6

x, x^{2} + y^{2} - z^{2} = 4

x, (y - x)^{2} + (z - x)^{2} = (y + x)^{2}

x^{2} - 4 x + \frac{7}{4} = 0

What are the solutions to the equation 4x^2+64x=0 ?
The solutions to the equation 4x^2+64x=0 are x=0,x=-16
Find the zeros of 4x^2+64x=0
The zeros of 4x^2+64x=0 are x=0,x=-16