What are the solutions to the equation 6^2+b^2=14^2 ?

The solutions to the equation 6^2+b^2=14^2 are b=4sqrt(10),b=-4sqrt(10)

Find the zeros of 6^2+b^2=14^2

The zeros of 6^2+b^2=14^2 are b=4sqrt(10),b=-4sqrt(10)

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6^{2} + b^{2} = 1 4^{2}

b = 410, b = - 410

Decimal Notation

b = 12.64911 \dots, b = - 12.64911 \dots

Solution steps

6^{2} + b^{2} = 1 4^{2}

Move

6^{2}

to the right side

b^{2} = 160

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 160, b = - 160

160 = 410

- 160 = - 410

b = 410, b = - 410

3 x^{2} + 7 x - 8 = 0

y^{2} + 6 y - 2 = 0

0 = \frac{5}{5} - \frac{x}{5} - x^{2}

x^{2} + 14 x - 6 = 0

5 x^{2} - 43 x - 18 = 0

What are the solutions to the equation 6^2+b^2=14^2 ?
The solutions to the equation 6^2+b^2=14^2 are b=4sqrt(10),b=-4sqrt(10)
Find the zeros of 6^2+b^2=14^2
The zeros of 6^2+b^2=14^2 are b=4sqrt(10),b=-4sqrt(10)