What are the solutions to the equation 19y^2-13y+2=y^2 ?

The solutions to the equation 19y^2-13y+2=y^2 are y= 1/2 ,y= 2/9

Find the zeros of 19y^2-13y+2=y^2

The zeros of 19y^2-13y+2=y^2 are y= 1/2 ,y= 2/9

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19 y^{2} - 13 y + 2 = y^{2}

y = \frac{1}{2}, y = \frac{2}{9}

Decimal Notation

y = 0.5, y = 0.22222 \dots

Solution steps

19 y^{2} - 13 y + 2 = y^{2}

Move

y^{2}

to the left side

18 y^{2} - 13 y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 18 \cdot 2}{2 \cdot 18}

(- 13)^{2} - 4 \cdot 18 \cdot 2 = 5

y_{1, 2} = \frac{- ( - 13 ) \pm 5}{2 \cdot 18}

Separate the solutions

y_{1} = \frac{- ( - 13 ) + 5}{2 \cdot 18}, y_{2} = \frac{- ( - 13 ) - 5}{2 \cdot 18}

y = \frac{- ( - 13 ) + 5}{2 \cdot 18} : \frac{1}{2}

y = \frac{- ( - 13 ) - 5}{2 \cdot 18} : \frac{2}{9}

The solutions to the quadratic equation are:

y = \frac{1}{2}, y = \frac{2}{9}

x^{2} + 2 x - 11 = 4

8 x^{2} - 5 = 0

25 x^{2} + 100 = 0

3 x^{2} = 9 x + 4

72 y = 6 y^{2}

What are the solutions to the equation 19y^2-13y+2=y^2 ?
The solutions to the equation 19y^2-13y+2=y^2 are y= 1/2 ,y= 2/9
Find the zeros of 19y^2-13y+2=y^2
The zeros of 19y^2-13y+2=y^2 are y= 1/2 ,y= 2/9