What are the solutions to the equation 4x^2+7x=0 ?

The solutions to the equation 4x^2+7x=0 are x=0,x=-7/4

Find the zeros of 4x^2+7x=0

The zeros of 4x^2+7x=0 are x=0,x=-7/4

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4 x^{2} + 7 x = 0

x = 0, x = - \frac{7}{4}

Decimal Notation

x = 0, x = - 1.75

Solution steps

4 x^{2} + 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

7^{2} - 4 \cdot 4 \cdot 0 = 7

x_{1, 2} = \frac{- 7 \pm 7}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 7 + 7}{2 \cdot 4}, x_{2} = \frac{- 7 - 7}{2 \cdot 4}

x = \frac{- 7 + 7}{2 \cdot 4} : 0

x = \frac{- 7 - 7}{2 \cdot 4} : - \frac{7}{4}

The solutions to the quadratic equation are:

x = 0, x = - \frac{7}{4}

\frac{( x ^{3} y ^{2} ) ^{\frac{3}{2}}}{( x ^{- 1} y ^{- \frac{2}{3}} ) ^{\frac{1}{4}}}

\frac{2 ( x - 3 )}{3} = \frac{x + 1}{2}

6 (x + 1) + 2 \geq 5 x + 12

x^{2} + 10 x + 25

- 775 - 147

What are the solutions to the equation 4x^2+7x=0 ?
The solutions to the equation 4x^2+7x=0 are x=0,x=-7/4
Find the zeros of 4x^2+7x=0
The zeros of 4x^2+7x=0 are x=0,x=-7/4