What are the solutions to the equation 10x(x-2)=45x[ x/5-1/9 ] ?

The solutions to the equation 10x(x-2)=45x[ x/5-1/9 ] are x=0,x=15

Find the zeros of 10x(x-2)=45x[ x/5-1/9 ]

The zeros of 10x(x-2)=45x[ x/5-1/9 ] are x=0,x=15

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

10 x (x - 2) = 45 x [\frac{x}{5} - \frac{1}{9}]

x = 0, x = 15

Solution steps

10 x (x - 2) = 45 x [\frac{x}{5} - \frac{1}{9}]

Move

45 x [\frac{x}{5} - \frac{1}{9}]

to the left side

10 x (x - 2) - 45 x [\frac{x}{5} - \frac{1}{9}] = 0

Factor

10 x (x - 2) - 45 x (\frac{x}{5} - \frac{1}{9}) : 5 x (\frac{x}{5} - 3)

5 x (\frac{x}{5} - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or \frac{x}{5} - 3 = 0

Solve

\frac{x}{5} - 3 = 0 : x = 15

The solutions to the quadratic equation are:

x = 0, x = 15

18 x^{2} - 18 x - 108 = 0

4 x^{2} - 30 = 2

m^{2} + 2 m - 2 = 0

(m - 2) x^{2} - (m + 7) x + 2 (9 m + 1) = 0

84 x (x + 2) = 90 - 13 x

What are the solutions to the equation 10x(x-2)=45x[ x/5-1/9 ] ?
The solutions to the equation 10x(x-2)=45x[ x/5-1/9 ] are x=0,x=15
Find the zeros of 10x(x-2)=45x[ x/5-1/9 ]
The zeros of 10x(x-2)=45x[ x/5-1/9 ] are x=0,x=15