What are the solutions to the equation quadraticformula x^2+2x-15=0 ?

The solutions to the equation quadraticformula x^2+2x-15=0 are x=3,x=-5

Find the zeros of quadraticformula x^2+2x-15=0

The zeros of quadraticformula x^2+2x-15=0 are x=3,x=-5

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x^{2} + 2 x - 15 = 0

x = 3, x = - 5

Solution steps

x^{2} + 2 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 15) = 8

x_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 8}{2 \cdot 1}, x_{2} = \frac{- 2 - 8}{2 \cdot 1}

x = \frac{- 2 + 8}{2 \cdot 1} : 3

x = \frac{- 2 - 8}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 3, x = - 5

(s + 4)^{2} = 0

(x - 4)^{2} + (x - 3)^{2} = 25

V = \frac{0.005}{2} (1000) (6.5 - V - 0.5)^{2}

12 = 2 \cdot 3 \cdot x^{2}

- 2 x^{2} + 140 x = 0

What are the solutions to the equation quadraticformula x^2+2x-15=0 ?
The solutions to the equation quadraticformula x^2+2x-15=0 are x=3,x=-5
Find the zeros of quadraticformula x^2+2x-15=0
The zeros of quadraticformula x^2+2x-15=0 are x=3,x=-5