What are the solutions to the equation 25^2=x^2+7^2 ?

The solutions to the equation 25^2=x^2+7^2 are x=24,x=-24

Find the zeros of 25^2=x^2+7^2

The zeros of 25^2=x^2+7^2 are x=24,x=-24

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2 5^{2} = x^{2} + 7^{2}

x = 24, x = - 24

Solution steps

2 5^{2} = x^{2} + 7^{2}

Switch sides

x^{2} + 7^{2} = 2 5^{2}

Move

7^{2}

to the right side

x^{2} = 576

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 576, x = - 576

576 = 24

- 576 = - 24

x = 24, x = - 24

3 x^{2} - 5 x = 4 - 3 x^{2}

72 x^{2} = 8 x

x^{1} - 5 x^{2} = 0, - x^{1} + 5 x^{2} = 0

3 x^{2} - 15 x - 14 = 7 x^{2} - 20 x - 23

9 x^{2} + 121 = 0

What are the solutions to the equation 25^2=x^2+7^2 ?
The solutions to the equation 25^2=x^2+7^2 are x=24,x=-24
Find the zeros of 25^2=x^2+7^2
The zeros of 25^2=x^2+7^2 are x=24,x=-24