What are the solutions to the equation 12x^2+14x-6=0 ?

The solutions to the equation 12x^2+14x-6=0 are x= 1/3 ,x=-3/2

Find the zeros of 12x^2+14x-6=0

The zeros of 12x^2+14x-6=0 are x= 1/3 ,x=-3/2

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12 x^{2} + 14 x - 6 = 0

x = \frac{1}{3}, x = - \frac{3}{2}

Decimal Notation

x = 0.33333 \dots, x = - 1.5

Solution steps

12 x^{2} + 14 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 12 ( - 6 )}{2 \cdot 12}

1 4^{2} - 4 \cdot 12 (- 6) = 22

x_{1, 2} = \frac{- 14 \pm 22}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 14 + 22}{2 \cdot 12}, x_{2} = \frac{- 14 - 22}{2 \cdot 12}

x = \frac{- 14 + 22}{2 \cdot 12} : \frac{1}{3}

x = \frac{- 14 - 22}{2 \cdot 12} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{3}{2}

- y^{2} + 6 y

x, y^{3} x + y^{2} x^{2} = 6

(x + 7)^{2} + x^{2} = 1 3^{2}

2 x^{2} - 11 x + 5 = 0

d^{2} - 5 d = 0

What are the solutions to the equation 12x^2+14x-6=0 ?
The solutions to the equation 12x^2+14x-6=0 are x= 1/3 ,x=-3/2
Find the zeros of 12x^2+14x-6=0
The zeros of 12x^2+14x-6=0 are x= 1/3 ,x=-3/2