What are the solutions to the equation 3v^2+7v=40 ?

The solutions to the equation 3v^2+7v=40 are v= 8/3 ,v=-5

Find the zeros of 3v^2+7v=40

The zeros of 3v^2+7v=40 are v= 8/3 ,v=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 v^{2} + 7 v = 40

v = \frac{8}{3}, v = - 5

Decimal Notation

v = 2.66666 \dots, v = - 5

Solution steps

3 v^{2} + 7 v = 40

Move

40

to the left side

3 v^{2} + 7 v - 40 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 40 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 40) = 23

v_{1, 2} = \frac{- 7 \pm 23}{2 \cdot 3}

Separate the solutions

v_{1} = \frac{- 7 + 23}{2 \cdot 3}, v_{2} = \frac{- 7 - 23}{2 \cdot 3}

v = \frac{- 7 + 23}{2 \cdot 3} : \frac{8}{3}

v = \frac{- 7 - 23}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

v = \frac{8}{3}, v = - 5

4 n^{2} - 24 n - 56 = 8

3 Q^{2} + 5 Q + 7 = - Q + 16

z, x^{2} + y^{2} + z^{2} = 16

4 m^{2} + 6 = 4 m + 1

x^{2} + 21 x + 38 = 0

What are the solutions to the equation 3v^2+7v=40 ?
The solutions to the equation 3v^2+7v=40 are v= 8/3 ,v=-5
Find the zeros of 3v^2+7v=40
The zeros of 3v^2+7v=40 are v= 8/3 ,v=-5