What are the solutions to the equation 9x^2+10x=5 ?

The solutions to the equation 9x^2+10x=5 are x=(-5+sqrt(70))/9 ,x=-(5+sqrt(70))/9

Find the zeros of 9x^2+10x=5

The zeros of 9x^2+10x=5 are x=(-5+sqrt(70))/9 ,x=-(5+sqrt(70))/9

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9 x^{2} + 10 x = 5

x = \frac{- 5 + 70}{9}, x = - \frac{5 + 70}{9}

Decimal Notation

x = 0.37406 \dots, x = - 1.48517 \dots

Solution steps

9 x^{2} + 10 x = 5

Move

5

to the left side

9 x^{2} + 10 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 9 ( - 5 )}{2 \cdot 9}

1 0^{2} - 4 \cdot 9 (- 5) = 270

x_{1, 2} = \frac{- 10 \pm 2 70}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 10 + 2 70}{2 \cdot 9}, x_{2} = \frac{- 10 - 2 70}{2 \cdot 9}

x = \frac{- 10 + 2 70}{2 \cdot 9} : \frac{- 5 + 70}{9}

x = \frac{- 10 - 2 70}{2 \cdot 9} : - \frac{5 + 70}{9}

The solutions to the quadratic equation are:

x = \frac{- 5 + 70}{9}, x = - \frac{5 + 70}{9}

x, - 2 x^{2} + y^{3} - 7 y + x = 0

5^{2} = a^{2} + (\frac{5}{2})^{2}

r, (2 - r)^{2} + (4 - r)^{2} = (r + 2)^{2}

5.7614 a^{2} + 2593 a - 516461.55 = 0

2 t^{2} + t - 3 = 0

What are the solutions to the equation 9x^2+10x=5 ?
The solutions to the equation 9x^2+10x=5 are x=(-5+sqrt(70))/9 ,x=-(5+sqrt(70))/9
Find the zeros of 9x^2+10x=5
The zeros of 9x^2+10x=5 are x=(-5+sqrt(70))/9 ,x=-(5+sqrt(70))/9