What are the solutions to the equation m^2-3m+1=0 ?

The solutions to the equation m^2-3m+1=0 are m=(3+sqrt(5))/2 ,m=(3-sqrt(5))/2

Find the zeros of m^2-3m+1=0

The zeros of m^2-3m+1=0 are m=(3+sqrt(5))/2 ,m=(3-sqrt(5))/2

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m^{2} - 3 m + 1 = 0

m = \frac{3 + 5}{2}, m = \frac{3 - 5}{2}

Decimal Notation

m = 2.61803 \dots, m = 0.38196 \dots

Solution steps

m^{2} - 3 m + 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 1 = 5

m_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 3 ) + 5}{2 \cdot 1}, m_{2} = \frac{- ( - 3 ) - 5}{2 \cdot 1}

m = \frac{- ( - 3 ) + 5}{2 \cdot 1} : \frac{3 + 5}{2}

m = \frac{- ( - 3 ) - 5}{2 \cdot 1} : \frac{3 - 5}{2}

The solutions to the quadratic equation are:

m = \frac{3 + 5}{2}, m = \frac{3 - 5}{2}

r^{2} - 6 r + 14 = 0

49 n^{2} - 6 = 75

3 x^{2} - 4 = 27 - x

x, 2 x^{2} - x y + y^{2} = 8

X, I = X^{2} + 2 X + 4

What are the solutions to the equation m^2-3m+1=0 ?
The solutions to the equation m^2-3m+1=0 are m=(3+sqrt(5))/2 ,m=(3-sqrt(5))/2
Find the zeros of m^2-3m+1=0
The zeros of m^2-3m+1=0 are m=(3+sqrt(5))/2 ,m=(3-sqrt(5))/2