What are the solutions to the equation 3x^2+2x+12=-13x ?

The solutions to the equation 3x^2+2x+12=-13x are x=-1,x=-4

Find the zeros of 3x^2+2x+12=-13x

The zeros of 3x^2+2x+12=-13x are x=-1,x=-4

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3 x^{2} + 2 x + 12 = - 13 x

x = - 1, x = - 4

Solution steps

3 x^{2} + 2 x + 12 = - 13 x

Move

13 x

to the left side

3 x^{2} + 15 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

1 5^{2} - 4 \cdot 3 \cdot 12 = 9

x_{1, 2} = \frac{- 15 \pm 9}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 15 + 9}{2 \cdot 3}, x_{2} = \frac{- 15 - 9}{2 \cdot 3}

x = \frac{- 15 + 9}{2 \cdot 3} : - 1

x = \frac{- 15 - 9}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = - 1, x = - 4

6 x^{2} - 6 x - 5 = 0

x^{2} + 88 x = 16.64

x, x^{2} y - 3 x^{2} = 75

(3 x - 1)^{2} - (x + 5)^{2} = 0

c, A = \frac{1}{3} b c^{2}

What are the solutions to the equation 3x^2+2x+12=-13x ?
The solutions to the equation 3x^2+2x+12=-13x are x=-1,x=-4
Find the zeros of 3x^2+2x+12=-13x
The zeros of 3x^2+2x+12=-13x are x=-1,x=-4