What are the solutions to the equation completesquare 12x^2+24x-6=0 ?

The solutions to the equation completesquare 12x^2+24x-6=0 are x=sqrt(3/2)-1,x=-sqrt(3/2)-1

Find the zeros of completesquare 12x^2+24x-6=0

The zeros of completesquare 12x^2+24x-6=0 are x=sqrt(3/2)-1,x=-sqrt(3/2)-1

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12 x^{2} + 24 x - 6 = 0

x = \frac{3}{2} - 1, x = - \frac{3}{2} - 1

Decimal Notation

x = 0.22474 \dots, x = - 2.22474 \dots

Solution steps

12 x^{2} + 24 x - 6 = 0

Move

6

to the right side

12 x^{2} + 24 x = 6

Divide both sides by

12

\frac{12 x ^{2} + 24 x}{12} = \frac{6}{12}

x^{2} + 2 x = \frac{1}{2}

Rewrite in the form

(x + a)^{2} = b

(x + 1)^{2} = \frac{3}{2}

For

the solutions are

f (x) = a, - a

Solve

x + 1 = \frac{3}{2} : x = \frac{3}{2} - 1

Solve

x + 1 = - \frac{3}{2} : x = - \frac{3}{2} - 1

The solutions to the quadratic equation are:

x = \frac{3}{2} - 1, x = - \frac{3}{2} - 1

z^{2} = - 13

z^{2} = - 36

3 x^{2} + 2 x + 1 = x^{2} - 3 x + 4

3 x^{2} + 12 x - 1

\frac{x ^{2}}{2 9 ^{2}} - \frac{3 6 ^{2}}{58.3 3 ^{2}} = 1

What are the solutions to the equation completesquare 12x^2+24x-6=0 ?
The solutions to the equation completesquare 12x^2+24x-6=0 are x=sqrt(3/2)-1,x=-sqrt(3/2)-1
Find the zeros of completesquare 12x^2+24x-6=0
The zeros of completesquare 12x^2+24x-6=0 are x=sqrt(3/2)-1,x=-sqrt(3/2)-1