What are the solutions to the equation 9p^2-24p+14=0 ?

The solutions to the equation 9p^2-24p+14=0 are p=(4+sqrt(2))/3 ,p=(4-sqrt(2))/3

Find the zeros of 9p^2-24p+14=0

The zeros of 9p^2-24p+14=0 are p=(4+sqrt(2))/3 ,p=(4-sqrt(2))/3

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9 p^{2} - 24 p + 14 = 0

p = \frac{4 + 2}{3}, p = \frac{4 - 2}{3}

Decimal Notation

p = 1.80473 \dots, p = 0.86192 \dots

Solution steps

9 p^{2} - 24 p + 14 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 9 \cdot 14}{2 \cdot 9}

(- 24)^{2} - 4 \cdot 9 \cdot 14 = 62

p_{1, 2} = \frac{- ( - 24 ) \pm 6 2}{2 \cdot 9}

Separate the solutions

p_{1} = \frac{- ( - 24 ) + 6 2}{2 \cdot 9}, p_{2} = \frac{- ( - 24 ) - 6 2}{2 \cdot 9}

p = \frac{- ( - 24 ) + 6 2}{2 \cdot 9} : \frac{4 + 2}{3}

p = \frac{- ( - 24 ) - 6 2}{2 \cdot 9} : \frac{4 - 2}{3}

The solutions to the quadratic equation are:

p = \frac{4 + 2}{3}, p = \frac{4 - 2}{3}

(y - 2) (y - 3) = 9 y + 6

u^{2} - 11 u + 28 = 0

q, m \cdot a = k \cdot \frac{q ^{2}}{r ^{2}}

2 x^{2} + 6 x + 4 = 24

9.08 = 0.001 (0.725 x^{2} + 15.417 x + 607.732)

What are the solutions to the equation 9p^2-24p+14=0 ?
The solutions to the equation 9p^2-24p+14=0 are p=(4+sqrt(2))/3 ,p=(4-sqrt(2))/3
Find the zeros of 9p^2-24p+14=0
The zeros of 9p^2-24p+14=0 are p=(4+sqrt(2))/3 ,p=(4-sqrt(2))/3