What are the solutions to the equation (5x-1)(x+1)=0 ?

The solutions to the equation (5x-1)(x+1)=0 are x= 1/5 ,x=-1

Find the zeros of (5x-1)(x+1)=0

The zeros of (5x-1)(x+1)=0 are x= 1/5 ,x=-1

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(5 x - 1) (x + 1) = 0

x = \frac{1}{5}, x = - 1

Decimal Notation

x = 0.2, x = - 1

Solution steps

(5 x - 1) (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x - 1 = 0 or x + 1 = 0

Solve

5 x - 1 = 0 : x = \frac{1}{5}

Solve

x + 1 = 0 : x = - 1

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - 1

x^{2} + 5 = 40

2 x^{2} - 7 + 3 = 0

u^{2} + 10 u + 21 = 0

(x + 15)^{2} = 49

4 x^{2} - 32 x - 64 = 0

What are the solutions to the equation (5x-1)(x+1)=0 ?
The solutions to the equation (5x-1)(x+1)=0 are x= 1/5 ,x=-1
Find the zeros of (5x-1)(x+1)=0
The zeros of (5x-1)(x+1)=0 are x= 1/5 ,x=-1