What are the solutions to the equation x^2+16x=-60 ?

The solutions to the equation x^2+16x=-60 are x=-6,x=-10

Find the zeros of x^2+16x=-60

The zeros of x^2+16x=-60 are x=-6,x=-10

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x^{2} + 16 x = - 60

x = - 6, x = - 10

Solution steps

x^{2} + 16 x = - 60

Move

60

to the left side

x^{2} + 16 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 60}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 60 = 4

x_{1, 2} = \frac{- 16 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 4}{2 \cdot 1}, x_{2} = \frac{- 16 - 4}{2 \cdot 1}

x = \frac{- 16 + 4}{2 \cdot 1} : - 6

x = \frac{- 16 - 4}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 6, x = - 10

6 x^{2} - 12 x + 4 = 0

\frac{1}{2} y^{2} - 3 = y + 1

3 r^{2} + 30 r + 8 = 0

\frac{1}{2} y^{2} - 3 = y - 1

x^{2} + 1.3 = 0

What are the solutions to the equation x^2+16x=-60 ?
The solutions to the equation x^2+16x=-60 are x=-6,x=-10
Find the zeros of x^2+16x=-60
The zeros of x^2+16x=-60 are x=-6,x=-10