What are the solutions to the equation p^2-3p+5=0 ?

The solutions to the equation p^2-3p+5=0 are p= 3/2+i(sqrt(11))/2 ,p= 3/2-i(sqrt(11))/2

Find the zeros of p^2-3p+5=0

The zeros of p^2-3p+5=0 are p= 3/2+i(sqrt(11))/2 ,p= 3/2-i(sqrt(11))/2

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p^{2} - 3 p + 5 = 0

p = \frac{3}{2} + i \frac{11}{2}, p = \frac{3}{2} - i \frac{11}{2}

Solution steps

p^{2} - 3 p + 5 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 5 : 11 i

p_{1, 2} = \frac{- ( - 3 ) \pm 11 i}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 3 ) + 11 i}{2 \cdot 1}, p_{2} = \frac{- ( - 3 ) - 11 i}{2 \cdot 1}

p = \frac{- ( - 3 ) + 11 i}{2 \cdot 1} : \frac{3}{2} + i \frac{11}{2}

p = \frac{- ( - 3 ) - 11 i}{2 \cdot 1} : \frac{3}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

p = \frac{3}{2} + i \frac{11}{2}, p = \frac{3}{2} - i \frac{11}{2}

a, (a + b + c) (a + b - c) = 3 ab

(x + 1) (x + 6) = 0

y^{2} + 24 y

x^{2} + 48 x = 0

n^{2} = 5 n - 6

What are the solutions to the equation p^2-3p+5=0 ?
The solutions to the equation p^2-3p+5=0 are p= 3/2+i(sqrt(11))/2 ,p= 3/2-i(sqrt(11))/2
Find the zeros of p^2-3p+5=0
The zeros of p^2-3p+5=0 are p= 3/2+i(sqrt(11))/2 ,p= 3/2-i(sqrt(11))/2