What are the solutions to the equation m^2-10m-16=0 ?

The solutions to the equation m^2-10m-16=0 are m=5+sqrt(41),m=5-sqrt(41)

Find the zeros of m^2-10m-16=0

The zeros of m^2-10m-16=0 are m=5+sqrt(41),m=5-sqrt(41)

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m^{2} - 10 m - 16 = 0

m = 5 + 41, m = 5 - 41

Decimal Notation

m = 11.40312 \dots, m = - 1.40312 \dots

Solution steps

m^{2} - 10 m - 16 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 16) = 241

m_{1, 2} = \frac{- ( - 10 ) \pm 2 41}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 10 ) + 2 41}{2 \cdot 1}, m_{2} = \frac{- ( - 10 ) - 2 41}{2 \cdot 1}

m = \frac{- ( - 10 ) + 2 41}{2 \cdot 1} : 5 + 41

m = \frac{- ( - 10 ) - 2 41}{2 \cdot 1} : 5 - 41

The solutions to the quadratic equation are:

m = 5 + 41, m = 5 - 41

4 - 12 x^{2} = 2 x

- 4.9 t^{2} + 12 t + 15 = 0

1 = (1 - y) (2 - y)

3 x^{2} + 5 = 32

x, 9 x^{2} - k x + 1 = 0

What are the solutions to the equation m^2-10m-16=0 ?
The solutions to the equation m^2-10m-16=0 are m=5+sqrt(41),m=5-sqrt(41)
Find the zeros of m^2-10m-16=0
The zeros of m^2-10m-16=0 are m=5+sqrt(41),m=5-sqrt(41)