What are the solutions to the equation 2x^1+8x^2=10 ?

The solutions to the equation 2x^1+8x^2=10 are x=1,x=-5/4

Find the zeros of 2x^1+8x^2=10

The zeros of 2x^1+8x^2=10 are x=1,x=-5/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{1} + 8 x^{2} = 10

x = 1, x = - \frac{5}{4}

Decimal Notation

x = 1, x = - 1.25

Solution steps

2 x^{1} + 8 x^{2} = 10

Refine

2 x + 8 x^{2} = 10

Move

10

to the left side

2 x + 8 x^{2} - 10 = 0

Write in the standard form

a x^{2} + b x + c = 0

8 x^{2} + 2 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 8 ( - 10 )}{2 \cdot 8}

2^{2} - 4 \cdot 8 (- 10) = 18

x_{1, 2} = \frac{- 2 \pm 18}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 2 + 18}{2 \cdot 8}, x_{2} = \frac{- 2 - 18}{2 \cdot 8}

x = \frac{- 2 + 18}{2 \cdot 8} : 1

x = \frac{- 2 - 18}{2 \cdot 8} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = 1, x = - \frac{5}{4}

x^{2} + 9 x + 25 = 0

5 x^{2} - 38 = 187

2 x^{2} + b x = 3

- 0.5358 x^{2} - 7.2142 x + 184.57 = 0

3 x^{2} - 8 x = 0

What are the solutions to the equation 2x^1+8x^2=10 ?
The solutions to the equation 2x^1+8x^2=10 are x=1,x=-5/4
Find the zeros of 2x^1+8x^2=10
The zeros of 2x^1+8x^2=10 are x=1,x=-5/4