What are the solutions to the equation 2x^2-2=-18 ?

The solutions to the equation 2x^2-2=-18 are x=2sqrt(2)i,x=-2sqrt(2)i

Find the zeros of 2x^2-2=-18

The zeros of 2x^2-2=-18 are x=2sqrt(2)i,x=-2sqrt(2)i

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2 x^{2} - 2 = - 18

x = 22 i, x = - 22 i

Solution steps

2 x^{2} - 2 = - 18

Move

2

to the right side

2 x^{2} = - 16

Divide both sides by

2

x^{2} = - 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 8, x = - - 8

- 8 = 22 i

- - 8 = - 22 i

x = 22 i, x = - 22 i

0.0138 x + \frac{( - 9.47 \cdot 1 0 ^{- 4} )}{2} x^{2} = 0.0111 x + \frac{( 15.15 \cdot 1 0 ^{- 4} )}{2} x^{2}

12 - 36 x + 18 x^{2} = 0

9 (2 x^{2} + 2) - 2 = 3 (4 x^{2} - 2) - 3 x^{2} - 2 x

3 t^{2} - 18 t = 0

49 m^{(2)} = 49 m - 12

What are the solutions to the equation 2x^2-2=-18 ?
The solutions to the equation 2x^2-2=-18 are x=2sqrt(2)i,x=-2sqrt(2)i
Find the zeros of 2x^2-2=-18
The zeros of 2x^2-2=-18 are x=2sqrt(2)i,x=-2sqrt(2)i