What are the solutions to the equation 50=4.9t^2 ?

The solutions to the equation 50=4.9t^2 are t=(10sqrt(5))/7 ,t=-(10sqrt(5))/7

Find the zeros of 50=4.9t^2

The zeros of 50=4.9t^2 are t=(10sqrt(5))/7 ,t=-(10sqrt(5))/7

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50 = 4.9 t^{2}

t = \frac{10 5}{7}, t = - \frac{10 5}{7}

Decimal Notation

t = 3.19438 \dots, t = - 3.19438 \dots

Solution steps

50 = 4.9 t^{2}

Switch sides

4.9 t^{2} = 50

Multiply both sides by

10

49 t^{2} = 500

Divide both sides by

49

t^{2} = \frac{500}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{500}{49}, t = - \frac{500}{49}

\frac{500}{49} = \frac{10 5}{7}

- \frac{500}{49} = - \frac{10 5}{7}

t = \frac{10 5}{7}, t = - \frac{10 5}{7}

- 5 x^{2} - 13 x + 5 = - 7 - 11 x

2646 - 504 x + 18 x^{2} = 0

x^{2} + \frac{2}{3} x - 4 = 0

5 x^{2} + 50 = 55

x^{2} + 7 x - 56 = 0

What are the solutions to the equation 50=4.9t^2 ?
The solutions to the equation 50=4.9t^2 are t=(10sqrt(5))/7 ,t=-(10sqrt(5))/7
Find the zeros of 50=4.9t^2
The zeros of 50=4.9t^2 are t=(10sqrt(5))/7 ,t=-(10sqrt(5))/7